11111213303 has 4 divisors (see below), whose sum is σ = 11129519040. Its totient is φ = 11092907568.

The previous prime is 11111213299. The next prime is 11111213317. The reversal of 11111213303 is 30331211111.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 30331211111 = 1511 ⋅20073601.

It is a cyclic number.

It is not a de Polignac number, because 11111213303 - 2² = 11111213299 is a prime.

It is a super-2 number, since 2×11111213303² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11111213353) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9151958 + ... + 9153171.

It is an arithmetic number, because the mean of its divisors is an integer number (2782379760).

Almost surely, 2^11111213303 is an apocalyptic number.

11111213303 is a deficient number, since it is larger than the sum of its proper divisors (18305737).

11111213303 is an equidigital number, since it uses as much as digits as its factorization.

11111213303 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 18305736.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 11111213303 its reverse (30331211111), we get a palindrome (41442424414).

The spelling of 11111213303 in words is "eleven billion, one hundred eleven million, two hundred thirteen thousand, three hundred three".