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11111224343 = 291190332189
BaseRepresentation
bin10100101100100011…
…11101010000010111
31001200100201200100112
422112101331100113
5140223433134333
65034320033235
7542226564032
oct122621752027
931610650315
1011111224343
114791aa633a
1221a116281b
131080c9b07b
14775984019
1545070e948
hex29647d417

11111224343 has 8 divisors (see below), whose sum is σ = 11495692800. Its totient is φ = 10726844128.

The previous prime is 11111224337. The next prime is 11111224427. The reversal of 11111224343 is 34342211111.

11111224343 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 11111224343 - 26 = 11111224279 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11111224303) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 329093 + ... + 361281.

It is an arithmetic number, because the mean of its divisors is an integer number (1436961600).

Almost surely, 211111224343 is an apocalyptic number.

11111224343 is a deficient number, since it is larger than the sum of its proper divisors (384468457).

11111224343 is a wasteful number, since it uses less digits than its factorization.

11111224343 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 44121.

The product of its digits is 576, while the sum is 23.

Adding to 11111224343 its reverse (34342211111), we get a palindrome (45453435454).

The spelling of 11111224343 in words is "eleven billion, one hundred eleven million, two hundred twenty-four thousand, three hundred forty-three".

Divisors: 1 29 11903 32189 345187 933481 383145667 11111224343