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11111242015 = 52222248403
BaseRepresentation
bin10100101100100100…
…00001100100011111
31001200100202120121001
422112102001210133
5140223434221030
65034320251131
7542226666406
oct122622014437
931610676531
1011111242015
114792008645
1221a1170aa7
131080ca6123
1477598a63d
15450714cca
hex29648191f

11111242015 has 4 divisors (see below), whose sum is σ = 13333490424. Its totient is φ = 8888993608.

The previous prime is 11111242001. The next prime is 11111242031. The reversal of 11111242015 is 51024211111.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 11111242015 - 27 = 11111241887 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11111241983 and 11111242001.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1111124197 + ... + 1111124206.

It is an arithmetic number, because the mean of its divisors is an integer number (3333372606).

Almost surely, 211111242015 is an apocalyptic number.

11111242015 is a deficient number, since it is larger than the sum of its proper divisors (2222248409).

11111242015 is an equidigital number, since it uses as much as digits as its factorization.

11111242015 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2222248408.

The product of its (nonzero) digits is 80, while the sum is 19.

Adding to 11111242015 its reverse (51024211111), we get a palindrome (62135453126).

The spelling of 11111242015 in words is "eleven billion, one hundred eleven million, two hundred forty-two thousand, fifteen".

Divisors: 1 5 2222248403 11111242015