111113000423 has 4 divisors (see below), whose sum is σ = 111114087600. Its totient is φ = 111111913248.

The previous prime is 111113000419. The next prime is 111113000429. The reversal of 111113000423 is 324000311111.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 324000311111 = 1933 ⋅167615267.

It is a cyclic number.

It is not a de Polignac number, because 111113000423 - 2² = 111113000419 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (111113000429) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 372290 + ... + 600687.

It is an arithmetic number, because the mean of its divisors is an integer number (27778521900).

Almost surely, 2^111113000423 is an apocalyptic number.

111113000423 is a deficient number, since it is larger than the sum of its proper divisors (1087177).

111113000423 is an equidigital number, since it uses as much as digits as its factorization.

111113000423 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1087176.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 111113000423 its reverse (324000311111), we get a palindrome (435113311534).

The spelling of 111113000423 in words is "one hundred eleven billion, one hundred thirteen million, four hundred twenty-three", and thus it is an aban number.