11112111120013 has 4 divisors (see below), whose sum is σ = 11128973201280. Its totient is φ = 11095249038748.

The previous prime is 11112111119987. The next prime is 11112111120029. The reversal of 11112111120013 is 31002111121111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11112111120013 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11112111120073) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8431039645 + ... + 8431040962.

It is an arithmetic number, because the mean of its divisors is an integer number (2782243300320).

Almost surely, 2^{11112111120013} is an apocalyptic number.

It is an amenable number.

11112111120013 is a deficient number, since it is larger than the sum of its proper divisors (16862081267).

11112111120013 is an equidigital number, since it uses as much as digits as its factorization.

11112111120013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 16862081266.

The product of its (nonzero) digits is 12, while the sum is 16.

Adding to 11112111120013 its reverse (31002111121111), we get a palindrome (42114222241124).

The spelling of 11112111120013 in words is "eleven trillion, one hundred twelve billion, one hundred eleven million, one hundred twenty thousand, thirteen".