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11112531044055 = 357105833628991
BaseRepresentation
bin1010000110110101011001…
…1101110010011011010111
31110100100101101200000101220
42201231112131302123113
52424031430421402210
635345005402221423
72224565610240060
oct241552635623327
943310341600356
1011112531044055
1135a4886086971
1212b58241b4873
13627ba40cc65c
142a5bc696b567
151440e0ab0c70
hexa1b567726d7

11112531044055 has 16 divisors (see below), whose sum is σ = 20320056766464. Its totient is φ = 5080014191520.

The previous prime is 11112531044009. The next prime is 11112531044081. The reversal of 11112531044055 is 55044013521111.

It is not a de Polignac number, because 11112531044055 - 28 = 11112531043799 is a prime.

It is a super-2 number, since 2×111125310440552 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 52916814391 + ... + 52916814600.

It is an arithmetic number, because the mean of its divisors is an integer number (1270003547904).

Almost surely, 211112531044055 is an apocalyptic number.

11112531044055 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

11112531044055 is a deficient number, since it is larger than the sum of its proper divisors (9207525722409).

11112531044055 is a wasteful number, since it uses less digits than its factorization.

11112531044055 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 105833629006.

The product of its (nonzero) digits is 12000, while the sum is 33.

Adding to 11112531044055 its reverse (55044013521111), we get a palindrome (66156544565166).

The spelling of 11112531044055 in words is "eleven trillion, one hundred twelve billion, five hundred thirty-one million, forty-four thousand, fifty-five".

Divisors: 1 3 5 7 15 21 35 105 105833628991 317500886973 529168144955 740835402937 1587504434865 2222506208811 3704177014685 11112531044055