11113001011203 has 32 divisors (see below), whose sum is σ = 18413775184896. Its totient is φ = 5804892010368.

The previous prime is 11113001011199. The next prime is 11113001011249. The reversal of 11113001011203 is 30211010031111.

It is not a de Polignac number, because 11113001011203 - 2² = 11113001011199 is a prime.

It is a super-3 number, since 3×11113001011203³ (a number of 40 digits) contains 333 as substring.

It is not an unprimeable number, because it can be changed into a prime (11113001011003) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 197578500 + ... + 197634737.

It is an arithmetic number, because the mean of its divisors is an integer number (575430474528).

Almost surely, 2^{11113001011203} is an apocalyptic number.

11113001011203 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

11113001011203 is a deficient number, since it is larger than the sum of its proper divisors (7300774173693).

11113001011203 is a wasteful number, since it uses less digits than its factorization.

11113001011203 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 395213363.

The product of its (nonzero) digits is 18, while the sum is 15.

Adding to 11113001011203 its reverse (30211010031111), we get a palindrome (41324011042314).

The spelling of 11113001011203 in words is "eleven trillion, one hundred thirteen billion, one million, eleven thousand, two hundred three".