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11113040433 = 3112379718371
BaseRepresentation
bin10100101100110001…
…11000101000110001
31001200111010221120010
422112120320220301
5140224414243213
65034423005133
7542251166535
oct122630705061
931614127503
1011113040433
114793026840
1221a18997a9
131081485891
14775cd7bc5
1545096cac3
hex296638a31

11113040433 has 32 divisors (see below), whose sum is σ = 16889306112. Its totient is φ = 6433908800.

The previous prime is 11113040423. The next prime is 11113040461. The reversal of 11113040433 is 33404031111.

It is not a de Polignac number, because 11113040433 - 24 = 11113040417 is a prime.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (11113040423) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 595738 + ... + 614108.

It is an arithmetic number, because the mean of its divisors is an integer number (527790816).

Almost surely, 211113040433 is an apocalyptic number.

It is an amenable number.

11113040433 is a deficient number, since it is larger than the sum of its proper divisors (5776265679).

11113040433 is a wasteful number, since it uses less digits than its factorization.

11113040433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 19205.

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 11113040433 its reverse (33404031111), we get a palindrome (44517071544).

The spelling of 11113040433 in words is "eleven billion, one hundred thirteen million, forty thousand, four hundred thirty-three".

Divisors: 1 3 11 23 33 69 253 759 797 2391 8767 18331 18371 26301 54993 55113 201641 202081 422533 604923 606243 1267599 4647863 13943589 14641687 43925061 161058557 336758801 483175671 1010276403 3704346811 11113040433