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11113131000000 = 2635610136677
BaseRepresentation
bin1010000110110111101000…
…1110011100000011000000
31110100101221012120221020110
42201231322032130003000
52424034143014000000
635345145113311320
72224616513623551
oct241557216340300
943311835527213
1011113131000000
1135a5063804727
1212b5971105540
13627c6b4b1183
142a5c42502328
151441285c0850
hexa1b7a39c0c0

11113131000000 has 392 divisors, whose sum is σ = 37118807060688. Its totient is φ = 2934080000000.

The previous prime is 11113130999977. The next prime is 11113131000019. The reversal of 11113131000000 is 13131111.

It is a super-2 number, since 2×111131310000002 (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (12).

It is a self number, because there is not a number n which added to its sum of digits gives 11113131000000.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 55 ways as a sum of consecutive naturals, for example, 302981662 + ... + 303018338.

Almost surely, 211113131000000 is an apocalyptic number.

11113131000000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 11113131000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (18559403530344).

11113131000000 is an abundant number, since it is smaller than the sum of its proper divisors (26005676060688).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11113131000000 is an frugal number, since it uses more digits than its factorization.

11113131000000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 36823 (or 36788 counting only the distinct ones).

The product of its (nonzero) digits is 9, while the sum is 12.

Adding to 11113131000000 its reverse (13131111), we get a palindrome (11113144131111).

The spelling of 11113131000000 in words is "eleven trillion, one hundred thirteen billion, one hundred thirty-one million", and thus it is an aban number.