Base | Representation |
---|---|
bin | 1010000110110111101001… |
… | …1110100000011110100111 |
3 | 1110100101221111111221122022 |
4 | 2201231322132200132213 |
5 | 2424034200103244310 |
6 | 35345145343453355 |
7 | 2224616564500013 |
oct | 241557236403647 |
9 | 43311844457568 |
10 | 11113135212455 |
11 | 35a50661215a1 |
12 | 12b59725b725b |
13 | 627c6c327653 |
14 | 2a5c42cbb543 |
15 | 144128b53a55 |
hex | a1b7a7a07a7 |
11113135212455 has 8 divisors (see below), whose sum is σ = 13336736248032. Its totient is φ = 8889858841248.
The previous prime is 11113135212449. The next prime is 11113135212559. The reversal of 11113135212455 is 55421253131111.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 11113135212455 - 28 = 11113135212199 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 81090779 + ... + 81227708.
It is an arithmetic number, because the mean of its divisors is an integer number (1667092031004).
Almost surely, 211113135212455 is an apocalyptic number.
11113135212455 is a deficient number, since it is larger than the sum of its proper divisors (2223601035577).
11113135212455 is a wasteful number, since it uses less digits than its factorization.
11113135212455 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 162332185.
The product of its digits is 18000, while the sum is 35.
Adding to 11113135212455 its reverse (55421253131111), we get a palindrome (66534388343566).
The spelling of 11113135212455 in words is "eleven trillion, one hundred thirteen billion, one hundred thirty-five million, two hundred twelve thousand, four hundred fifty-five".
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