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11113141120402 = 210155015550101
BaseRepresentation
bin1010000110110111101011…
…0101000010110110010010
31110100101221220122002211011
42201231322311002312102
52424034203111323102
635345150114241134
72224616665634236
oct241557265026622
943311856562734
1011113141120402
1135a50694972a2
1212b59745861aa
13627c70615789
142a5c439b85c6
1514412941e2d7
hexa1b7ad42d92

11113141120402 has 8 divisors (see below), whose sum is σ = 16834758331212. Its totient is φ = 5501555010000.

The previous prime is 11113141120379. The next prime is 11113141120489. The reversal of 11113141120402 is 20402114131111.

11113141120402 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It can be written as a sum of positive squares in 2 ways, for example, as 6812042580121 + 4301098540281 = 2609989^2 + 2073909^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 27507774849 + ... + 27507775252.

Almost surely, 211113141120402 is an apocalyptic number.

11113141120402 is a deficient number, since it is larger than the sum of its proper divisors (5721617210810).

11113141120402 is a wasteful number, since it uses less digits than its factorization.

11113141120402 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 55015550204.

The product of its (nonzero) digits is 192, while the sum is 22.

Adding to 11113141120402 its reverse (20402114131111), we get a palindrome (31515255251513).

The spelling of 11113141120402 in words is "eleven trillion, one hundred thirteen billion, one hundred forty-one million, one hundred twenty thousand, four hundred two".

Divisors: 1 2 101 202 55015550101 110031100202 5556570560201 11113141120402