Base | Representation |
---|---|
bin | 1010000110110111111011… |
… | …1111101010010000000111 |
3 | 1110100102010210010222012200 |
4 | 2201231332333222100013 |
5 | 2424034324004341403 |
6 | 35345201052245543 |
7 | 2224621505000154 |
oct | 241557677522007 |
9 | 43312123128180 |
10 | 11113211012103 |
11 | 35a50a4993a32 |
12 | 12b5993a708b3 |
13 | 627c81c46c05 |
14 | 2a5c4cdad22b |
15 | 144130627ca3 |
hex | a1b7efea407 |
11113211012103 has 6 divisors (see below), whose sum is σ = 16052415906384. Its totient is φ = 7408807341396.
The previous prime is 11113211012087. The next prime is 11113211012131. The reversal of 11113211012103 is 30121011231111.
It is not a de Polignac number, because 11113211012103 - 24 = 11113211012087 is a prime.
It is a super-2 number, since 2×111132110121032 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11113211013103) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 617400611775 + ... + 617400611792.
It is an arithmetic number, because the mean of its divisors is an integer number (2675402651064).
Almost surely, 211113211012103 is an apocalyptic number.
11113211012103 is a deficient number, since it is larger than the sum of its proper divisors (4939204894281).
11113211012103 is a wasteful number, since it uses less digits than its factorization.
11113211012103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1234801223573 (or 1234801223570 counting only the distinct ones).
The product of its (nonzero) digits is 36, while the sum is 18.
Adding to 11113211012103 its reverse (30121011231111), we get a palindrome (41234222243214).
The spelling of 11113211012103 in words is "eleven trillion, one hundred thirteen billion, two hundred eleven million, twelve thousand, one hundred three".
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