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11113230431 = 178920113089
BaseRepresentation
bin10100101100110011…
…00111000001011111
31001200111111121012002
422112121213001133
5140224441333211
65034431032515
7542252620502
oct122631470137
931614447162
1011113230431
114793146566
1221a196b73b
1310815211c4
14775d47139
154509a903b
hex29666705f

11113230431 has 8 divisors (see below), whose sum is σ = 11128573200. Its totient is φ = 11097901440.

The previous prime is 11113230407. The next prime is 11113230433. The reversal of 11113230431 is 13403231111.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11113230431 is a prime.

It is a super-5 number, since 5×111132304315 (a number of 51 digits) contains 55555 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11113230433) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3596135 + ... + 3599223.

It is an arithmetic number, because the mean of its divisors is an integer number (1391071650).

Almost surely, 211113230431 is an apocalyptic number.

11113230431 is a deficient number, since it is larger than the sum of its proper divisors (15342769).

11113230431 is a wasteful number, since it uses less digits than its factorization.

11113230431 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6889.

The product of its (nonzero) digits is 216, while the sum is 20.

Adding to 11113230431 its reverse (13403231111), we get a palindrome (24516461542).

The spelling of 11113230431 in words is "eleven billion, one hundred thirteen million, two hundred thirty thousand, four hundred thirty-one".

Divisors: 1 1789 2011 3089 3597679 5526221 6211979 11113230431