Base | Representation |
---|---|
bin | 10000001011000000011… |
… | …100010100010100011111 |
3 | 10221020112111212010110000 |
4 | 100023000130110110133 |
5 | 121202001013223403 |
6 | 2210312115145343 |
7 | 143201540634660 |
oct | 20130034242437 |
9 | 3836474763400 |
10 | 1111330211103 |
11 | 399348a28322 |
12 | 15b4722a5253 |
13 | 80a4b24a7b8 |
14 | 3bb08173367 |
15 | 1dd9551a7a3 |
hex | 102c071451f |
1111330211103 has 80 divisors (see below), whose sum is σ = 2009631539520. Its totient is φ = 597473501184.
The previous prime is 1111330211083. The next prime is 1111330211143. The reversal of 1111330211103 is 3011120331111.
1111330211103 is a `hidden beast` number, since 1 + 111 + 330 + 211 + 10 + 3 = 666.
It is not a de Polignac number, because 1111330211103 - 25 = 1111330211071 is a prime.
It is a super-2 number, since 2×11113302111032 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1111330211143) by changing a digit.
It is a polite number, since it can be written in 79 ways as a sum of consecutive naturals, for example, 28598775 + ... + 28637607.
It is an arithmetic number, because the mean of its divisors is an integer number (25120394244).
Almost surely, 21111330211103 is an apocalyptic number.
1111330211103 is a deficient number, since it is larger than the sum of its proper divisors (898301328417).
1111330211103 is a wasteful number, since it uses less digits than its factorization.
1111330211103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 41838 (or 41829 counting only the distinct ones).
The product of its (nonzero) digits is 54, while the sum is 18.
Adding to 1111330211103 its reverse (3011120331111), we get a palindrome (4122450542214).
The spelling of 1111330211103 in words is "one trillion, one hundred eleven billion, three hundred thirty million, two hundred eleven thousand, one hundred three".
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