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11113313013000 = 23325311775314479
BaseRepresentation
bin1010000110111000010100…
…0100110000110100001000
31110100102101220002011010200
42201232011010300310020
52424040031112404000
635345215134412200
72224624153664652
oct241560504606410
943312356064120
1011113313013000
1135a51475217a0
1212b5a02061060
13627c9a10b383
142a5c5c7616d2
15144139575500
hexa1b85130d08

11113313013000 has 384 divisors, whose sum is σ = 40985931916800. Its totient is φ = 2693602944000.

The previous prime is 11113313012999. The next prime is 11113313013037. The reversal of 11113313013000 is 31031331111.

11113313013000 is a `hidden beast` number, since 1 + 1 + 1 + 1 + 331 + 30 + 1 + 300 + 0 = 666.

It is a super-2 number, since 2×111133130130002 (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is an unprimeable number.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 767539761 + ... + 767554239.

It is an arithmetic number, because the mean of its divisors is an integer number (106734197700).

Almost surely, 211113313013000 is an apocalyptic number.

11113313013000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 11113313013000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (20492965958400).

11113313013000 is an abundant number, since it is smaller than the sum of its proper divisors (29872618903800).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11113313013000 is a wasteful number, since it uses less digits than its factorization.

11113313013000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 22270 (or 22253 counting only the distinct ones).

The product of its (nonzero) digits is 81, while the sum is 18.

Adding to 11113313013000 its reverse (31031331111), we get a palindrome (11144344344111).

The spelling of 11113313013000 in words is "eleven trillion, one hundred thirteen billion, three hundred thirteen million, thirteen thousand".