Base | Representation |
---|---|
bin | 10000001011000100100… |
… | …110100010101110110001 |
3 | 10221020201101011210102000 |
4 | 100023010212202232301 |
5 | 121202121400003213 |
6 | 2210323051044213 |
7 | 143203346063262 |
oct | 20130446425661 |
9 | 3836641153360 |
10 | 1111400000433 |
11 | 399384365058 |
12 | 15b491740669 |
13 | 80a5c844468 |
14 | 3bb1353c969 |
15 | 1dd9b703c73 |
hex | 102c49a2bb1 |
1111400000433 has 32 divisors (see below), whose sum is σ = 1670754086400. Its totient is φ = 730074452688.
The previous prime is 1111400000429. The next prime is 1111400000453. The reversal of 1111400000433 is 3340000041111.
It is not a de Polignac number, because 1111400000433 - 22 = 1111400000429 is a prime.
It is not an unprimeable number, because it can be changed into a prime (1111400000423) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 195066 + ... + 1503612.
It is an arithmetic number, because the mean of its divisors is an integer number (52211065200).
Almost surely, 21111400000433 is an apocalyptic number.
It is an amenable number.
1111400000433 is a deficient number, since it is larger than the sum of its proper divisors (559354085967).
1111400000433 is a wasteful number, since it uses less digits than its factorization.
1111400000433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1309018 (or 1309012 counting only the distinct ones).
The product of its (nonzero) digits is 144, while the sum is 18.
Adding to 1111400000433 its reverse (3340000041111), we get a palindrome (4451400041544).
The spelling of 1111400000433 in words is "one trillion, one hundred eleven billion, four hundred million, four hundred thirty-three", and thus it is an aban number.
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