111141000341 has 4 divisors (see below), whose sum is σ = 127018286112. Its totient is φ = 95263714572.

The previous prime is 111141000331. The next prime is 111141000343. The reversal of 111141000341 is 143000141111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 143000141111 = 43 ⋅3325584677.

It is a cyclic number.

It is not a de Polignac number, because 111141000341 - 2⁶ = 111141000277 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (111141000343) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7938642875 + ... + 7938642888.

It is an arithmetic number, because the mean of its divisors is an integer number (31754571528).

Almost surely, 2^111141000341 is an apocalyptic number.

It is an amenable number.

111141000341 is a deficient number, since it is larger than the sum of its proper divisors (15877285771).

111141000341 is an equidigital number, since it uses as much as digits as its factorization.

111141000341 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 15877285770.

The product of its (nonzero) digits is 48, while the sum is 17.

Adding to 111141000341 its reverse (143000141111), we get a palindrome (254141141452).

The spelling of 111141000341 in words is "one hundred eleven billion, one hundred forty-one million, three hundred forty-one", and thus it is an aban number.