11114221120113 has 4 divisors (see below), whose sum is σ = 14818961493488. Its totient is φ = 7409480746740.

The previous prime is 11114221120097. The next prime is 11114221120127. The reversal of 11114221120113 is 31102112241111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 11114221120113 - 2⁴ = 11114221120097 is a prime.

It is a super-2 number, since 2×11114221120113² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 11114221120113.

It is not an unprimeable number, because it can be changed into a prime (11114221120153) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1852370186683 + ... + 1852370186688.

It is an arithmetic number, because the mean of its divisors is an integer number (3704740373372).

Almost surely, 2^{11114221120113} is an apocalyptic number.

It is an amenable number.

11114221120113 is a deficient number, since it is larger than the sum of its proper divisors (3704740373375).

11114221120113 is an equidigital number, since it uses as much as digits as its factorization.

11114221120113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3704740373374.

The product of its (nonzero) digits is 96, while the sum is 21.

Adding to 11114221120113 its reverse (31102112241111), we get a palindrome (42216333361224).

The spelling of 11114221120113 in words is "eleven trillion, one hundred fourteen billion, two hundred twenty-one million, one hundred twenty thousand, one hundred thirteen".