1111547113 has 4 divisors (see below), whose sum is σ = 1111622020. Its totient is φ = 1111472208.

The previous prime is 1111547093. The next prime is 1111547123. The reversal of 1111547113 is 3117451111.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 3117451111 = 47963 ⋅64997.

It can be written as a sum of positive squares in 2 ways, for example, as 1042773264 + 68773849 = 32292^2 + 8293^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1111547113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1111547123) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6870 + ... + 47647.

It is an arithmetic number, because the mean of its divisors is an integer number (277905505).

Almost surely, 2^1111547113 is an apocalyptic number.

It is an amenable number.

1111547113 is a deficient number, since it is larger than the sum of its proper divisors (74907).

1111547113 is an equidigital number, since it uses as much as digits as its factorization.

1111547113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 74906.

The product of its digits is 420, while the sum is 25.

The square root of 1111547113 is about 33339.8727202130. The cubic root of 1111547113 is about 1035.8796268590.

Adding to 1111547113 its reverse (3117451111), we get a palindrome (4228998224).

The spelling of 1111547113 in words is "one billion, one hundred eleven million, five hundred forty-seven thousand, one hundred thirteen".