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1112001115 = 5222400223
BaseRepresentation
bin100001001000111…
…1100101001011011
32212111102111202111
41002101330221123
54234133013430
6302202013151
736361565521
oct10221745133
92774374674
101112001115
11520771995
122704a71b7
131494c3334
14a7984311
1567956c2a
hex4247ca5b

1112001115 has 4 divisors (see below), whose sum is σ = 1334401344. Its totient is φ = 889600888.

The previous prime is 1112001103. The next prime is 1112001131. The reversal of 1112001115 is 5111002111.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1112001115 - 225 = 1078446683 is a prime.

It is a super-2 number, since 2×11120011152 = 2473092959522486450, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1112001095 and 1112001104.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 111200107 + ... + 111200116.

It is an arithmetic number, because the mean of its divisors is an integer number (333600336).

Almost surely, 21112001115 is an apocalyptic number.

1112001115 is a deficient number, since it is larger than the sum of its proper divisors (222400229).

1112001115 is an equidigital number, since it uses as much as digits as its factorization.

1112001115 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 222400228.

The product of its (nonzero) digits is 10, while the sum is 13.

The square root of 1112001115 is about 33346.6807193760. The cubic root of 1112001115 is about 1036.0206397477.

Adding to 1112001115 its reverse (5111002111), we get a palindrome (6223003226).

The spelling of 1112001115 in words is "one billion, one hundred twelve million, one thousand, one hundred fifteen".

Divisors: 1 5 222400223 1112001115