Base | Representation |
---|---|
bin | 1010000111010001101011… |
… | …0111111110010010010011 |
3 | 1110101001222100220101200020 |
4 | 2201310122313332102103 |
5 | 2424143002012210003 |
6 | 35352302501554523 |
7 | 2225254653466551 |
oct | 241643267762223 |
9 | 43331870811606 |
10 | 11120121210003 |
11 | 35a8020581993 |
12 | 12b71a2115a43 |
13 | 62881376a000 |
14 | 2a6306a30bd1 |
15 | 1443d7103d53 |
hex | a1d1adfe493 |
11120121210003 has 128 divisors (see below), whose sum is σ = 17317998028800. Its totient is φ = 6323466240000.
The previous prime is 11120121210001. The next prime is 11120121210059. The reversal of 11120121210003 is 30001212102111.
It is not a de Polignac number, because 11120121210003 - 21 = 11120121210001 is a prime.
It is not an unprimeable number, because it can be changed into a prime (11120121210001) by changing a digit.
It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 1996786803 + ... + 1996792371.
It is an arithmetic number, because the mean of its divisors is an integer number (135296859600).
Almost surely, 211120121210003 is an apocalyptic number.
11120121210003 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
11120121210003 is a deficient number, since it is larger than the sum of its proper divisors (6197876818797).
11120121210003 is a wasteful number, since it uses less digits than its factorization.
11120121210003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5950 (or 5924 counting only the distinct ones).
The product of its (nonzero) digits is 24, while the sum is 15.
Adding to 11120121210003 its reverse (30001212102111), we get a palindrome (41121333312114).
The spelling of 11120121210003 in words is "eleven trillion, one hundred twenty billion, one hundred twenty-one million, two hundred ten thousand, three".
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