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1112021020113 = 3370673673371
BaseRepresentation
bin10000001011101001100…
…111100010110111010001
310221022022122201212020220
4100023221213202313101
5121204404340120423
62210504433423253
7143224626466263
oct20135147426721
93838278655226
101112021020113
1139967296a363
1215b62570ab29
1380b2b3bc623
143bb71bd7b33
151ddd5ec49e3
hex102e99e2dd1

1112021020113 has 4 divisors (see below), whose sum is σ = 1482694693488. Its totient is φ = 741347346740.

The previous prime is 1112021020081. The next prime is 1112021020139. The reversal of 1112021020113 is 3110201202111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1112021020113 - 25 = 1112021020081 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1112021020092 and 1112021020101.

It is not an unprimeable number, because it can be changed into a prime (1112021020163) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 185336836683 + ... + 185336836688.

It is an arithmetic number, because the mean of its divisors is an integer number (370673673372).

Almost surely, 21112021020113 is an apocalyptic number.

It is an amenable number.

1112021020113 is a deficient number, since it is larger than the sum of its proper divisors (370673673375).

1112021020113 is an equidigital number, since it uses as much as digits as its factorization.

1112021020113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 370673673374.

The product of its (nonzero) digits is 24, while the sum is 15.

Adding to 1112021020113 its reverse (3110201202111), we get a palindrome (4222222222224).

The spelling of 1112021020113 in words is "one trillion, one hundred twelve billion, twenty-one million, twenty thousand, one hundred thirteen".

Divisors: 1 3 370673673371 1112021020113