11120213 has 4 divisors (see below), whose sum is σ = 11975628. Its totient is φ = 10264800.

The previous prime is 11120209. The next prime is 11120243. The reversal of 11120213 is 31202111.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 31202111 = 277 ⋅112643.

It can be written as a sum of positive squares in 2 ways, for example, as 3179089 + 7941124 = 1783^2 + 2818^2 .

It is not a de Polignac number, because 11120213 - 2² = 11120209 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11120194 and 11120203.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11120243) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 427688 + ... + 427713.

It is an arithmetic number, because the mean of its divisors is an integer number (2993907).

Almost surely, 2^11120213 is an apocalyptic number.

11120213 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

11120213 is a deficient number, since it is larger than the sum of its proper divisors (855415).

11120213 is an equidigital number, since it uses as much as digits as its factorization.

11120213 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 855414.

The product of its (nonzero) digits is 12, while the sum is 11.

The square root of 11120213 is about 3334.6983371813. The cubic root of 11120213 is about 223.2052311073.

Adding to 11120213 its reverse (31202111), we get a palindrome (42322324).

The spelling of 11120213 in words is "eleven million, one hundred twenty thousand, two hundred thirteen".