Base | Representation |
---|---|
bin | 1010000111010010011110… |
… | …0000010100011100101011 |
3 | 1110101002112010122012010020 |
4 | 2201310213200110130223 |
5 | 2424143420234110011 |
6 | 35352335511451523 |
7 | 2225263135601124 |
oct | 241644740243453 |
9 | 43332463565106 |
10 | 11120333113131 |
11 | 35a811a154940 |
12 | 12b7241086ba3 |
13 | 628848631188 |
14 | 2a6326c3104b |
15 | 1443eaa10006 |
hex | a1d2781472b |
11120333113131 has 16 divisors (see below), whose sum is σ = 16175095799808. Its totient is φ = 6739568402400.
The previous prime is 11120333113091. The next prime is 11120333113199. The reversal of 11120333113131 is 13131133302111.
It is not a de Polignac number, because 11120333113131 - 210 = 11120333112107 is a prime.
It is a super-2 number, since 2×111203331131312 (a number of 27 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (11120333153131) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 10061910 + ... + 11112276.
It is an arithmetic number, because the mean of its divisors is an integer number (1010943487488).
Almost surely, 211120333113131 is an apocalyptic number.
11120333113131 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
11120333113131 is a deficient number, since it is larger than the sum of its proper divisors (5054762686677).
11120333113131 is a wasteful number, since it uses less digits than its factorization.
11120333113131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1371202.
The product of its (nonzero) digits is 486, while the sum is 24.
Adding to 11120333113131 its reverse (13131133302111), we get a palindrome (24251466415242).
The spelling of 11120333113131 in words is "eleven trillion, one hundred twenty billion, three hundred thirty-three million, one hundred thirteen thousand, one hundred thirty-one".
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