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11121311313103 = 59188496801917
BaseRepresentation
bin1010000111010110000111…
…0011110110110011001111
31110101012001022021220012211
42201311201303312303033
52424202421144004403
635353020534011251
72225326314265105
oct241654163666317
943335038256184
1011121311313103
1135a8581338a72
1212b74747a6b27
136289731a7824
142a63bab05c75
1514445683706d
hexa1d61cf6ccf

11121311313103 has 4 divisors (see below), whose sum is σ = 11309808115080. Its totient is φ = 10932814511128.

The previous prime is 11121311313089. The next prime is 11121311313107. The reversal of 11121311313103 is 30131311312111.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 11121311313103 - 213 = 11121311304911 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11121311313107) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 94248400900 + ... + 94248401017.

It is an arithmetic number, because the mean of its divisors is an integer number (2827452028770).

Almost surely, 211121311313103 is an apocalyptic number.

11121311313103 is a deficient number, since it is larger than the sum of its proper divisors (188496801977).

11121311313103 is an equidigital number, since it uses as much as digits as its factorization.

11121311313103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 188496801976.

The product of its (nonzero) digits is 162, while the sum is 22.

Adding to 11121311313103 its reverse (30131311312111), we get a palindrome (41252622625214).

The spelling of 11121311313103 in words is "eleven trillion, one hundred twenty-one billion, three hundred eleven million, three hundred thirteen thousand, one hundred three".

Divisors: 1 59 188496801917 11121311313103