Base | Representation |
---|---|
bin | 10100101101110110… |
… | …11100100011010001 |
3 | 1001201010012020112200 |
4 | 22112323130203101 |
5 | 140234224203213 |
6 | 5035345113413 |
7 | 542421202533 |
oct | 122673344321 |
9 | 31633166480 |
10 | 11122100433 |
11 | 4798154744 |
12 | 21a4928869 |
13 | 1083308622 |
14 | 7771b5853 |
15 | 45165c273 |
hex | 296edc8d1 |
11122100433 has 48 divisors (see below), whose sum is σ = 17627737920. Its totient is φ = 6732367488.
The previous prime is 11122100393. The next prime is 11122100453. The reversal of 11122100433 is 33400122111.
11122100433 is a `hidden beast` number, since 1 + 11 + 221 + 0 + 0 + 433 = 666.
It is not a de Polignac number, because 11122100433 - 28 = 11122100177 is a prime.
It is a super-2 number, since 2×111221004332 (a number of 21 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (11122100453) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 410791 + ... + 437027.
It is an arithmetic number, because the mean of its divisors is an integer number (367244540).
Almost surely, 211122100433 is an apocalyptic number.
It is an amenable number.
11122100433 is a deficient number, since it is larger than the sum of its proper divisors (6505637487).
11122100433 is a wasteful number, since it uses less digits than its factorization.
11122100433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 26366 (or 26363 counting only the distinct ones).
The product of its (nonzero) digits is 144, while the sum is 18.
Adding to 11122100433 its reverse (33400122111), we get a palindrome (44522222544).
The spelling of 11122100433 in words is "eleven billion, one hundred twenty-two million, one hundred thousand, four hundred thirty-three".
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