11122101413 has 4 divisors (see below), whose sum is σ = 11190335328. Its totient is φ = 11053867500.

The previous prime is 11122101407. The next prime is 11122101427. The reversal of 11122101413 is 31410122111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31410122111 = 29 ⋅1083107659.

It is a cyclic number.

It is not a de Polignac number, because 11122101413 - 2¹⁸ = 11121839269 is a prime.

It is a super-2 number, since 2×11122101413² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11122101391 and 11122101400.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11122101013) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 34116713 + ... + 34117038.

It is an arithmetic number, because the mean of its divisors is an integer number (2797583832).

Almost surely, 2^11122101413 is an apocalyptic number.

It is an amenable number.

11122101413 is a deficient number, since it is larger than the sum of its proper divisors (68233915).

11122101413 is an equidigital number, since it uses as much as digits as its factorization.

11122101413 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 68233914.

The product of its (nonzero) digits is 48, while the sum is 17.

Adding to 11122101413 its reverse (31410122111), we get a palindrome (42532223524).

The spelling of 11122101413 in words is "eleven billion, one hundred twenty-two million, one hundred one thousand, four hundred thirteen".