Base | Representation |
---|---|
bin | 11001010010011110101110… |
… | …111000111110000111110111 |
3 | 112120210122010112202212010102 |
4 | 121102132232320332013313 |
5 | 104034221314222100043 |
6 | 1032314135034144315 |
7 | 32266313563021655 |
oct | 3122365670760767 |
9 | 476718115685112 |
10 | 111221112300023 |
11 | 32490677401820 |
12 | 1058349158209b |
13 | 4a0a14b83018b |
14 | 1d671b8371dd5 |
15 | ccd1b2b2e6b8 |
hex | 6527aee3e1f7 |
111221112300023 has 4 divisors (see below), whose sum is σ = 121332122509128. Its totient is φ = 101110102090920.
The previous prime is 111221112299987. The next prime is 111221112300037. The reversal of 111221112300023 is 320003211122111.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 111221112300023 - 226 = 111221045191159 is a prime.
It is a super-2 number, since 2×1112211123000232 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 111221112299968 and 111221112300004.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (111221112302023) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5055505104536 + ... + 5055505104557.
It is an arithmetic number, because the mean of its divisors is an integer number (30333030627282).
Almost surely, 2111221112300023 is an apocalyptic number.
111221112300023 is a deficient number, since it is larger than the sum of its proper divisors (10111010209105).
111221112300023 is a wasteful number, since it uses less digits than its factorization.
111221112300023 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 10111010209104.
The product of its (nonzero) digits is 144, while the sum is 20.
Adding to 111221112300023 its reverse (320003211122111), we get a palindrome (431224323422134).
The spelling of 111221112300023 in words is "one hundred eleven trillion, two hundred twenty-one billion, one hundred twelve million, three hundred thousand, twenty-three".
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