Base | Representation |
---|---|
bin | 10100101101110111… |
… | …00110101110110101 |
3 | 1001201010021100202010 |
4 | 22112323212232311 |
5 | 140234232022013 |
6 | 5035350034433 |
7 | 542421435234 |
oct | 122673465665 |
9 | 31633240663 |
10 | 11122142133 |
11 | 4798183003 |
12 | 21a4948a19 |
13 | 10833215bb |
14 | 7771c6b1b |
15 | 4516697c3 |
hex | 296ee6bb5 |
11122142133 has 4 divisors (see below), whose sum is σ = 14829522848. Its totient is φ = 7414761420.
The previous prime is 11122142117. The next prime is 11122142153. The reversal of 11122142133 is 33124122111.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 33124122111 = 3 ⋅11041374037.
It is not a de Polignac number, because 11122142133 - 24 = 11122142117 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11122142153) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1853690353 + ... + 1853690358.
It is an arithmetic number, because the mean of its divisors is an integer number (3707380712).
Almost surely, 211122142133 is an apocalyptic number.
It is an amenable number.
11122142133 is a deficient number, since it is larger than the sum of its proper divisors (3707380715).
11122142133 is an equidigital number, since it uses as much as digits as its factorization.
11122142133 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3707380714.
The product of its digits is 288, while the sum is 21.
Adding to 11122142133 its reverse (33124122111), we get a palindrome (44246264244).
The spelling of 11122142133 in words is "eleven billion, one hundred twenty-two million, one hundred forty-two thousand, one hundred thirty-three".
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