Base | Representation |
---|---|
bin | 11001010010100000100001… |
… | …001100111000011000011101 |
3 | 112120210211002012111022022111 |
4 | 121102200201030320120131 |
5 | 104034234231202401023 |
6 | 1032315053223514021 |
7 | 32266412241156505 |
oct | 3122404114703035 |
9 | 476724065438274 |
10 | 111223030122013 |
11 | 32491470a1a877 |
12 | 105839278b8911 |
13 | 4a0a395c639a4 |
14 | 1d6731ad58a05 |
15 | ccd2761ad00d |
hex | 65282133861d |
111223030122013 has 4 divisors (see below), whose sum is σ = 111223053369568. Its totient is φ = 111223006874460.
The previous prime is 111223030121911. The next prime is 111223030122049. The reversal of 111223030122013 is 310221030322111.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 111223030122013 - 29 = 111223030121501 is a prime.
It is a super-2 number, since 2×1112230301220132 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (111223030122613) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1519593 + ... + 14991838.
It is an arithmetic number, because the mean of its divisors is an integer number (27805763342392).
Almost surely, 2111223030122013 is an apocalyptic number.
It is an amenable number.
111223030122013 is a deficient number, since it is larger than the sum of its proper divisors (23247555).
111223030122013 is an equidigital number, since it uses as much as digits as its factorization.
111223030122013 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 23247554.
The product of its (nonzero) digits is 432, while the sum is 22.
Adding to 111223030122013 its reverse (310221030322111), we get a palindrome (421444060444124).
The spelling of 111223030122013 in words is "one hundred eleven trillion, two hundred twenty-three billion, thirty million, one hundred twenty-two thousand, thirteen".
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