Search a number
-
+
11122310210002 = 25561155105001
BaseRepresentation
bin1010000111011001110101…
…0110010110000111010010
31110101021121220220010011021
42201312131112112013102
52424211442403210002
635353304015510054
72225363133623005
oct241663526260722
943337556803137
1011122310210002
1135a8a44178aa2
1212b76b322832a
13628aa2119894
142a647364753c
151444b439b737
hexa1d9d5961d2

11122310210002 has 4 divisors (see below), whose sum is σ = 16683465315006. Its totient is φ = 5561155105000.

The previous prime is 11122310209993. The next prime is 11122310210017. The reversal of 11122310210002 is 20001201322111.

11122310210002 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 10505565430441 + 616744779561 = 3241229^2 + 785331^2 .

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2780577552499 + ... + 2780577552502.

Almost surely, 211122310210002 is an apocalyptic number.

11122310210002 is a deficient number, since it is larger than the sum of its proper divisors (5561155105004).

11122310210002 is an equidigital number, since it uses as much as digits as its factorization.

11122310210002 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5561155105003.

The product of its (nonzero) digits is 48, while the sum is 16.

Adding to 11122310210002 its reverse (20001201322111), we get a palindrome (31123511532113).

The spelling of 11122310210002 in words is "eleven trillion, one hundred twenty-two billion, three hundred ten million, two hundred ten thousand, two".

Divisors: 1 2 5561155105001 11122310210002