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111230001200213 = 715890000171459
BaseRepresentation
bin11001010010100111000000…
…101101011011110001010101
3112120211111002000210202211222
4121102213000231123301111
5104034343020301401323
61032322205050140125
732300050056310610
oct3122470055336125
9476744060722758
10111230001200213
1132494418a10025
1210585152421645
134a0ac3728162c
141d677bcb07177
15ccd5331b29c8
hex6529c0b5bc55

111230001200213 has 4 divisors (see below), whose sum is σ = 127120001371680. Its totient is φ = 95340001028748.

The previous prime is 111230001200189. The next prime is 111230001200233. The reversal of 111230001200213 is 312002100032111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 111230001200213 - 238 = 110955123293269 is a prime.

It is a super-2 number, since 2×1112300012002132 (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 111230001200191 and 111230001200200.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (111230001200233) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7945000085723 + ... + 7945000085736.

It is an arithmetic number, because the mean of its divisors is an integer number (31780000342920).

Almost surely, 2111230001200213 is an apocalyptic number.

It is an amenable number.

111230001200213 is a deficient number, since it is larger than the sum of its proper divisors (15890000171467).

111230001200213 is an equidigital number, since it uses as much as digits as its factorization.

111230001200213 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 15890000171466.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 111230001200213 its reverse (312002100032111), we get a palindrome (423232101232324).

The spelling of 111230001200213 in words is "one hundred eleven trillion, two hundred thirty billion, one million, two hundred thousand, two hundred thirteen".

Divisors: 1 7 15890000171459 111230001200213