Base | Representation |
---|---|
bin | 110011110010111010… |
… | …1010001011101111101 |
3 | 101122002211010001120010 |
4 | 1213211311101131331 |
5 | 3310244403130140 |
6 | 123033131413433 |
7 | 11015246335266 |
oct | 1474565213575 |
9 | 348084101503 |
10 | 111230130045 |
11 | 43199566011 |
12 | 196828b4279 |
13 | a6483105c8 |
14 | 555271796d |
15 | 2d600d5880 |
hex | 19e5d5177d |
111230130045 has 16 divisors (see below), whose sum is σ = 178369952832. Its totient is φ = 59188821120.
The previous prime is 111230130031. The next prime is 111230130079. The reversal of 111230130045 is 540031032111.
It is not a de Polignac number, because 111230130045 - 24 = 111230130029 is a prime.
It is a super-2 number, since 2×1112301300452 (a number of 23 digits) contains 22 as substring.
It is a Curzon number.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 8362816 + ... + 8376105.
It is an arithmetic number, because the mean of its divisors is an integer number (11148122052).
Almost surely, 2111230130045 is an apocalyptic number.
111230130045 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
111230130045 is a deficient number, since it is larger than the sum of its proper divisors (67139822787).
111230130045 is a wasteful number, since it uses less digits than its factorization.
111230130045 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 16739372.
The product of its (nonzero) digits is 360, while the sum is 21.
Adding to 111230130045 its reverse (540031032111), we get a palindrome (651261162156).
The spelling of 111230130045 in words is "one hundred eleven billion, two hundred thirty million, one hundred thirty thousand, forty-five".
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