Base | Representation |
---|---|
bin | 10000001011111010010… |
… | …111110101000101101101 |
3 | 10221100001020122212101111 |
4 | 100023322113311011231 |
5 | 121210443320110013 |
6 | 2210552354312021 |
7 | 143234611651411 |
oct | 20137227650555 |
9 | 3840036585344 |
10 | 1112302113133 |
11 | 3997a75aa742 |
12 | 15b6a3888611 |
13 | 80b746ca663 |
14 | 3bb9b288d41 |
15 | 1de009eb73d |
hex | 102fa5f516d |
1112302113133 has 4 divisors (see below), whose sum is σ = 1115925247360. Its totient is φ = 1108678978908.
The previous prime is 1112302113103. The next prime is 1112302113179. The reversal of 1112302113133 is 3313112032111.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1112302113133 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1112302113103) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1811566653 + ... + 1811567266.
It is an arithmetic number, because the mean of its divisors is an integer number (278981311840).
Almost surely, 21112302113133 is an apocalyptic number.
It is an amenable number.
1112302113133 is a deficient number, since it is larger than the sum of its proper divisors (3623134227).
1112302113133 is an equidigital number, since it uses as much as digits as its factorization.
1112302113133 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3623134226.
The product of its (nonzero) digits is 324, while the sum is 22.
Adding to 1112302113133 its reverse (3313112032111), we get a palindrome (4425414145244).
The spelling of 1112302113133 in words is "one trillion, one hundred twelve billion, three hundred two million, one hundred thirteen thousand, one hundred thirty-three".
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