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1112312210455 = 5222462442091
BaseRepresentation
bin10000001011111010111…
…110010110010000010111
310221100001221122212022101
4100023322332112100113
5121211003411213310
62210553354542531
7143235063534565
oct20137276262027
93840057585271
101112312210455
11399802276a36
1215b6a7137a47
1380b768245c4
143bb9c756a35
151de0184343a
hex102faf96417

1112312210455 has 4 divisors (see below), whose sum is σ = 1334774652552. Its totient is φ = 889849768360.

The previous prime is 1112312210413. The next prime is 1112312210473. The reversal of 1112312210455 is 5540122132111.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 1112312210455 - 211 = 1112312208407 is a prime.

It is a super-2 number, since 2×11123122104552 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 111231221041 + ... + 111231221050.

It is an arithmetic number, because the mean of its divisors is an integer number (333693663138).

Almost surely, 21112312210455 is an apocalyptic number.

1112312210455 is a deficient number, since it is larger than the sum of its proper divisors (222462442097).

1112312210455 is an equidigital number, since it uses as much as digits as its factorization.

1112312210455 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 222462442096.

The product of its (nonzero) digits is 2400, while the sum is 28.

Adding to 1112312210455 its reverse (5540122132111), we get a palindrome (6652434342566).

The spelling of 1112312210455 in words is "one trillion, one hundred twelve billion, three hundred twelve million, two hundred ten thousand, four hundred fifty-five".

Divisors: 1 5 222462442091 1112312210455