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1112320232013 = 3370773410671
BaseRepresentation
bin10000001011111011011…
…100111100101001001101
310221100002111202101211010
4100023323130330221031
5121211012434411023
62210554242515433
7143235221654214
oct20137334745115
93840074671733
101112320232013
11399806855721
1215b6a9965b79
1380b783a27a3
143bb9d84407b
151de023ca093
hex102fb73ca4d

1112320232013 has 4 divisors (see below), whose sum is σ = 1483093642688. Its totient is φ = 741546821340.

The previous prime is 1112320231999. The next prime is 1112320232053. The reversal of 1112320232013 is 3102320232111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 1112320232013 - 26 = 1112320231949 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1112320232053) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 185386705333 + ... + 185386705338.

It is an arithmetic number, because the mean of its divisors is an integer number (370773410672).

Almost surely, 21112320232013 is an apocalyptic number.

It is an amenable number.

1112320232013 is a deficient number, since it is larger than the sum of its proper divisors (370773410675).

1112320232013 is an equidigital number, since it uses as much as digits as its factorization.

1112320232013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 370773410674.

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 1112320232013 its reverse (3102320232111), we get a palindrome (4214640464124).

The spelling of 1112320232013 in words is "one trillion, one hundred twelve billion, three hundred twenty million, two hundred thirty-two thousand, thirteen".

Divisors: 1 3 370773410671 1112320232013