Base | Representation |
---|---|
bin | 10000001011111011011… |
… | …100111100101001001101 |
3 | 10221100002111202101211010 |
4 | 100023323130330221031 |
5 | 121211012434411023 |
6 | 2210554242515433 |
7 | 143235221654214 |
oct | 20137334745115 |
9 | 3840074671733 |
10 | 1112320232013 |
11 | 399806855721 |
12 | 15b6a9965b79 |
13 | 80b783a27a3 |
14 | 3bb9d84407b |
15 | 1de023ca093 |
hex | 102fb73ca4d |
1112320232013 has 4 divisors (see below), whose sum is σ = 1483093642688. Its totient is φ = 741546821340.
The previous prime is 1112320231999. The next prime is 1112320232053. The reversal of 1112320232013 is 3102320232111.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 1112320232013 - 26 = 1112320231949 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1112320232053) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 185386705333 + ... + 185386705338.
It is an arithmetic number, because the mean of its divisors is an integer number (370773410672).
Almost surely, 21112320232013 is an apocalyptic number.
It is an amenable number.
1112320232013 is a deficient number, since it is larger than the sum of its proper divisors (370773410675).
1112320232013 is an equidigital number, since it uses as much as digits as its factorization.
1112320232013 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 370773410674.
The product of its (nonzero) digits is 432, while the sum is 21.
Adding to 1112320232013 its reverse (3102320232111), we get a palindrome (4214640464124).
The spelling of 1112320232013 in words is "one trillion, one hundred twelve billion, three hundred twenty million, two hundred thirty-two thousand, thirteen".
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