111232131122113 has 4 divisors (see below), whose sum is σ = 111246248674240. Its totient is φ = 111218013569988.

The previous prime is 111232131122089. The next prime is 111232131122129. The reversal of 111232131122113 is 311221131232111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-111232131122113 is a prime.

It is a super-3 number, since 3×111232131122113³ (a number of 43 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (111232131122173) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7058764245 + ... + 7058780002.

It is an arithmetic number, because the mean of its divisors is an integer number (27811562168560).

Almost surely, 2^{111232131122113} is an apocalyptic number.

It is an amenable number.

111232131122113 is a deficient number, since it is larger than the sum of its proper divisors (14117552127).

111232131122113 is an equidigital number, since it uses as much as digits as its factorization.

111232131122113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 14117552126.

The product of its digits is 432, while the sum is 25.

Adding to 111232131122113 its reverse (311221131232111), we get a palindrome (422453262354224).

The spelling of 111232131122113 in words is "one hundred eleven trillion, two hundred thirty-two billion, one hundred thirty-one million, one hundred twenty-two thousand, one hundred thirteen".