Base | Representation |
---|---|
bin | 10000001011111011100… |
… | …001000100100101100011 |
3 | 10221100002120210022211020 |
4 | 100023323201010211203 |
5 | 121211013224004443 |
6 | 2210554322020523 |
7 | 143235234106146 |
oct | 20137341044543 |
9 | 3840076708736 |
10 | 1112321313123 |
11 | 3998074239a9 |
12 | 15b6aa1a7743 |
13 | 80b786908b7 |
14 | 3bb9da4605d |
15 | 1de02540583 |
hex | 102fb844963 |
1112321313123 has 4 divisors (see below), whose sum is σ = 1483095084168. Its totient is φ = 741547542080.
The previous prime is 1112321313107. The next prime is 1112321313127. The reversal of 1112321313123 is 3213131232111.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1112321313123 - 24 = 1112321313107 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1112321313093 and 1112321313102.
It is not an unprimeable number, because it can be changed into a prime (1112321313127) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 185386885518 + ... + 185386885523.
It is an arithmetic number, because the mean of its divisors is an integer number (370773771042).
Almost surely, 21112321313123 is an apocalyptic number.
1112321313123 is a deficient number, since it is larger than the sum of its proper divisors (370773771045).
1112321313123 is an equidigital number, since it uses as much as digits as its factorization.
1112321313123 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 370773771044.
The product of its digits is 648, while the sum is 24.
Adding to 1112321313123 its reverse (3213131232111), we get a palindrome (4325452545234).
The spelling of 1112321313123 in words is "one trillion, one hundred twelve billion, three hundred twenty-one million, three hundred thirteen thousand, one hundred twenty-three".
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