11123353 has 4 divisors (see below), whose sum is σ = 11131600. Its totient is φ = 11115108.

The previous prime is 11123323. The next prime is 11123393. The reversal of 11123353 is 35332111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 35332111 = 43 ⋅821677.

It is a cyclic number.

It is not a de Polignac number, because 11123353 - 2¹⁷ = 10992281 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 11123353.

It is not an unprimeable number, because it can be changed into a prime (11123323) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1575 + ... + 4972.

It is an arithmetic number, because the mean of its divisors is an integer number (2782900).

Almost surely, 2^11123353 is an apocalyptic number.

It is an amenable number.

11123353 is a deficient number, since it is larger than the sum of its proper divisors (8247).

11123353 is an equidigital number, since it uses as much as digits as its factorization.

11123353 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8246.

The product of its digits is 270, while the sum is 19.

The square root of 11123353 is about 3335.1691111546. The cubic root of 11123353 is about 223.2262378533.

Adding to 11123353 its reverse (35332111), we get a palindrome (46455464).

It can be divided in two parts, 11123 and 353, that added together give a triangular number (11476 = T₁₅₁).

The spelling of 11123353 in words is "eleven million, one hundred twenty-three thousand, three hundred fifty-three".