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11124112015 = 52224822403
BaseRepresentation
bin10100101110000110…
…00111101010001111
31001201020222102220201
422113003013222033
5140240233041030
65035500154331
7542444251312
oct122703075217
931636872821
1011124112015
1147992a9005
1221a55389a7
131083861103
1477757a979
154519082ca
hex2970c7a8f

11124112015 has 4 divisors (see below), whose sum is σ = 13348934424. Its totient is φ = 8899289608.

The previous prime is 11124112007. The next prime is 11124112063. The reversal of 11124112015 is 51021142111.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 11124112015 - 23 = 11124112007 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11124111983 and 11124112001.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1112411197 + ... + 1112411206.

It is an arithmetic number, because the mean of its divisors is an integer number (3337233606).

Almost surely, 211124112015 is an apocalyptic number.

11124112015 is a deficient number, since it is larger than the sum of its proper divisors (2224822409).

11124112015 is an equidigital number, since it uses as much as digits as its factorization.

11124112015 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2224822408.

The product of its (nonzero) digits is 80, while the sum is 19.

Adding to 11124112015 its reverse (51021142111), we get a palindrome (62145254126).

It can be divided in two parts, 111241 and 12015, that added together give a triangular number (123256 = T496).

The spelling of 11124112015 in words is "eleven billion, one hundred twenty-four million, one hundred twelve thousand, fifteen".

Divisors: 1 5 2224822403 11124112015