Base | Representation |
---|---|
bin | 10100101110001011… |
… | …10011000001001101 |
3 | 1001201022022002201111 |
4 | 22113011303001031 |
5 | 140240423021101 |
6 | 5035523212021 |
7 | 542453233525 |
oct | 122705630115 |
9 | 31638262644 |
10 | 11124813901 |
11 | 4799738383 |
12 | 21a5817011 |
13 | 1083a48726 |
14 | 7776c0685 |
15 | 4519e6251 |
hex | 29717304d |
11124813901 has 4 divisors (see below), whose sum is σ = 11249811900. Its totient is φ = 10999815904.
The previous prime is 11124813883. The next prime is 11124813907. The reversal of 11124813901 is 10931842111.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 6702696900 + 4422117001 = 81870^2 + 66499^2 .
It is a cyclic number.
It is not a de Polignac number, because 11124813901 - 213 = 11124805709 is a prime.
It is a super-2 number, since 2×111248139012 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11124813907) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 62498866 + ... + 62499043.
It is an arithmetic number, because the mean of its divisors is an integer number (2812452975).
Almost surely, 211124813901 is an apocalyptic number.
It is an amenable number.
11124813901 is a deficient number, since it is larger than the sum of its proper divisors (124997999).
11124813901 is an equidigital number, since it uses as much as digits as its factorization.
11124813901 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 124997998.
The product of its (nonzero) digits is 1728, while the sum is 31.
The spelling of 11124813901 in words is "eleven billion, one hundred twenty-four million, eight hundred thirteen thousand, nine hundred one".
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