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11130000333 = 326347140813
BaseRepresentation
bin10100101110110011…
…00101001111001101
31001201200001121011120
422113121211033031
5140243240002313
65040230311153
7542545304364
oct122731451715
931650047146
1011130000333
1147a165aa91
1221a74b84b9
131084b4331a
147782707db
154521bcd23
hex2976653cd

11130000333 has 8 divisors (see below), whose sum is σ = 14840669088. Its totient is φ = 7419665904.

The previous prime is 11130000247. The next prime is 11130000337. The reversal of 11130000333 is 33300003111.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 11130000333 - 213 = 11129992141 is a prime.

It is a super-2 number, since 2×111300003332 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11130000337) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 8635 + ... + 149447.

It is an arithmetic number, because the mean of its divisors is an integer number (1855083636).

Almost surely, 211130000333 is an apocalyptic number.

It is an amenable number.

11130000333 is a deficient number, since it is larger than the sum of its proper divisors (3710668755).

11130000333 is a wasteful number, since it uses less digits than its factorization.

11130000333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 167163.

The product of its (nonzero) digits is 81, while the sum is 15.

Adding to 11130000333 its reverse (33300003111), we get a palindrome (44430003444).

The spelling of 11130000333 in words is "eleven billion, one hundred thirty million, three hundred thirty-three", and thus it is an aban number.

Divisors: 1 3 26347 79041 140813 422439 3710000111 11130000333