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11130010241 = 71590001463
BaseRepresentation
bin10100101110110011…
…00111101010000001
31001201200002002202112
422113121213222001
5140243240311431
65040230425105
7542545345310
oct122731475201
931650062675
1011130010241
1147a1667479
1221a7502195
131084b4799c
14778274277
154521c0c2b
hex297667a81

11130010241 has 4 divisors (see below), whose sum is σ = 12720011712. Its totient is φ = 9540008772.

The previous prime is 11130010231. The next prime is 11130010249. The reversal of 11130010241 is 14201003111.

11130010241 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 11130010241 - 210 = 11130009217 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11130010249) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 795000725 + ... + 795000738.

It is an arithmetic number, because the mean of its divisors is an integer number (3180002928).

Almost surely, 211130010241 is an apocalyptic number.

It is an amenable number.

11130010241 is a deficient number, since it is larger than the sum of its proper divisors (1590001471).

11130010241 is an equidigital number, since it uses as much as digits as its factorization.

11130010241 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1590001470.

The product of its (nonzero) digits is 24, while the sum is 14.

Adding to 11130010241 its reverse (14201003111), we get a palindrome (25331013352).

The spelling of 11130010241 in words is "eleven billion, one hundred thirty million, ten thousand, two hundred forty-one".

Divisors: 1 7 1590001463 11130010241