Base | Representation |
---|---|
bin | 10100101110110011… |
… | …00111111001101101 |
3 | 1001201200002011010201 |
4 | 22113121213321231 |
5 | 140243240324440 |
6 | 5040230433501 |
7 | 542545351243 |
oct | 122731477155 |
9 | 31650064121 |
10 | 11130011245 |
11 | 47a1668201 |
12 | 21a7502891 |
13 | 1084b48292 |
14 | 778274793 |
15 | 4521c119a |
hex | 297667e6d |
11130011245 has 4 divisors (see below), whose sum is σ = 13356013500. Its totient is φ = 8904008992.
The previous prime is 11130011209. The next prime is 11130011267. The reversal of 11130011245 is 54211003111.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 54211003111 = 419 ⋅129381869.
It can be written as a sum of positive squares in 2 ways, for example, as 1991033641 + 9138977604 = 44621^2 + 95598^2 .
It is a cyclic number.
It is not a de Polignac number, because 11130011245 - 27 = 11130011117 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1113001120 + ... + 1113001129.
It is an arithmetic number, because the mean of its divisors is an integer number (3339003375).
Almost surely, 211130011245 is an apocalyptic number.
It is an amenable number.
11130011245 is a deficient number, since it is larger than the sum of its proper divisors (2226002255).
11130011245 is an equidigital number, since it uses as much as digits as its factorization.
11130011245 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2226002254.
The product of its (nonzero) digits is 120, while the sum is 19.
Adding to 11130011245 its reverse (54211003111), we get a palindrome (65341014356).
The spelling of 11130011245 in words is "eleven billion, one hundred thirty million, eleven thousand, two hundred forty-five".
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