11130020115 has 16 divisors (see below), whose sum is σ = 17826471168. Its totient is φ = 5929864416.

The previous prime is 11130020017. The next prime is 11130020129. The reversal of 11130020115 is 51102003111.

It is not a de Polignac number, because 11130020115 - 2¹⁸ = 11129757971 is a prime.

It is a super-2 number, since 2×11130020115² (a number of 21 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a junction number, because it is equal to n+sod(n) for n = 11130020094 and 11130020103.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 369157 + ... + 398166.

It is an arithmetic number, because the mean of its divisors is an integer number (1114154448).

Almost surely, 2^11130020115 is an apocalyptic number.

11130020115 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

11130020115 is a deficient number, since it is larger than the sum of its proper divisors (6696451053).

11130020115 is an equidigital number, since it uses as much as digits as its factorization.

11130020115 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 768298.

The product of its (nonzero) digits is 30, while the sum is 15.

Adding to 11130020115 its reverse (51102003111), we get a palindrome (62232023226).

The spelling of 11130020115 in words is "eleven billion, one hundred thirty million, twenty thousand, one hundred fifteen".