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11130052301 = 72729715153
BaseRepresentation
bin10100101110110011…
…10001111011001101
31001201200011020110022
422113121301323031
5140243243133201
65040231351525
7542545612034
oct122731617315
931650136408
1011130052301
1147a1696035
1221a75225a5
131084b60b84
1477828571b
154521cd41b
hex297671ecd

11130052301 has 8 divisors (see below), whose sum is σ = 11151276864. Its totient is φ = 11108845440.

The previous prime is 11130052259. The next prime is 11130052327. The reversal of 11130052301 is 10325003111.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11130052301 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 11130052301.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11130052391) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2157341 + ... + 2162493.

It is an arithmetic number, because the mean of its divisors is an integer number (1393909608).

Almost surely, 211130052301 is an apocalyptic number.

It is an amenable number.

11130052301 is a deficient number, since it is larger than the sum of its proper divisors (21224563).

11130052301 is an equidigital number, since it uses as much as digits as its factorization.

11130052301 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8851.

The product of its (nonzero) digits is 90, while the sum is 17.

Adding to 11130052301 its reverse (10325003111), we get a palindrome (21455055412).

The spelling of 11130052301 in words is "eleven billion, one hundred thirty million, fifty-two thousand, three hundred one".

Divisors: 1 727 2971 5153 2159917 3746231 15309563 11130052301