Base | Representation |
---|---|
bin | 11001010011101011000111… |
… | …000000001001001001111111 |
3 | 112121002110210220000020022211 |
4 | 121103223013000021021333 |
5 | 104042042243012241111 |
6 | 1032415540433521251 |
7 | 32305246050203620 |
oct | 3123530700111177 |
9 | 477073726006284 |
10 | 111303121212031 |
11 | 32512430292161 |
12 | 1059735a113227 |
13 | 4a14abac0c908 |
14 | 1d6b157c45a47 |
15 | cd03b2671521 |
hex | 653ac700927f |
111303121212031 has 4 divisors (see below), whose sum is σ = 127203567099472. Its totient is φ = 95402675324592.
The previous prime is 111303121212013. The next prime is 111303121212047. The reversal of 111303121212031 is 130212121303111.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 111303121212031 - 25 = 111303121211999 is a prime.
It is a super-2 number, since 2×1113031212120312 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 111303121211993 and 111303121212011.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (111303121212091) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7950222943710 + ... + 7950222943723.
It is an arithmetic number, because the mean of its divisors is an integer number (31800891774868).
Almost surely, 2111303121212031 is an apocalyptic number.
111303121212031 is a deficient number, since it is larger than the sum of its proper divisors (15900445887441).
111303121212031 is an equidigital number, since it uses as much as digits as its factorization.
111303121212031 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 15900445887440.
The product of its (nonzero) digits is 216, while the sum is 22.
Adding to 111303121212031 its reverse (130212121303111), we get a palindrome (241515242515142).
The spelling of 111303121212031 in words is "one hundred eleven trillion, three hundred three billion, one hundred twenty-one million, two hundred twelve thousand, thirty-one".
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