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111310200000 = 2634556871
BaseRepresentation
bin110011110101010011…
…0101101110011000000
3101122022101210000220000
41213222212231303000
53310430402400000
6123045111520000
711020241042346
oct1475246556300
9348271700800
10111310200000
114322a78482a
12196a5689000
13a65ba9678c
14555d1db996
152d67150000
hex19ea9adcc0

111310200000 has 420 divisors, whose sum is σ = 412481505744. Its totient is φ = 29678400000.

The previous prime is 111310199989. The next prime is 111310200031. The reversal of 111310200000 is 2013111.

It is a Harshad number since it is a multiple of its sum of digits (9).

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 59 ways as a sum of consecutive naturals, for example, 16196565 + ... + 16203435.

Almost surely, 2111310200000 is an apocalyptic number.

111310200000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 111310200000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (206240752872).

111310200000 is an abundant number, since it is smaller than the sum of its proper divisors (301171305744).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

111310200000 is an frugal number, since it uses more digits than its factorization.

111310200000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6920 (or 6881 counting only the distinct ones).

The product of its (nonzero) digits is 6, while the sum is 9.

Adding to 111310200000 its reverse (2013111), we get a palindrome (111312213111).

The spelling of 111310200000 in words is "one hundred eleven billion, three hundred ten million, two hundred thousand".