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111310312113000 = 2332537111312355457
BaseRepresentation
bin11001010011110001110011…
…100111010000001101101000
3112121010011101000221212000100
4121103301303213100031220
5104042202004400104000
61032423130151505400
732305622204642520
oct3123616347201550
9477104330855010
10111310312113000
1132515490374520
1210598826388260
134a156959353c0
141d6b63ac96680
15cd0683ae8a00
hex653c739d0368

111310312113000 has 768 divisors, whose sum is σ = 505146475491840. Its totient is φ = 21350227968000.

The previous prime is 111310312112941. The next prime is 111310312113031. The reversal of 111310312113000 is 311213013111.

111310312113000 is a `hidden beast` number, since 1 + 1 + 1 + 310 + 31 + 21 + 1 + 300 + 0 = 666.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 191 ways as a sum of consecutive naturals, for example, 2831272 + ... + 15186728.

It is an arithmetic number, because the mean of its divisors is an integer number (657742806630).

Almost surely, 2111310312113000 is an apocalyptic number.

111310312113000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 111310312113000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (252573237745920).

111310312113000 is an abundant number, since it is smaller than the sum of its proper divisors (393836163378840).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

111310312113000 is a wasteful number, since it uses less digits than its factorization.

111310312113000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12355515 (or 12355498 counting only the distinct ones).

The product of its (nonzero) digits is 54, while the sum is 18.

Adding to 111310312113000 its reverse (311213013111), we get a palindrome (111621525126111).

The spelling of 111310312113000 in words is "one hundred eleven trillion, three hundred ten billion, three hundred twelve million, one hundred thirteen thousand".