Base | Representation |
---|---|
bin | 110011110101010100… |
… | …1110001001011110111 |
3 | 101122022110021200201011 |
4 | 1213222221301023313 |
5 | 3310431104002221 |
6 | 123045141013051 |
7 | 11020250614540 |
oct | 1475251611367 |
9 | 348273250634 |
10 | 111311000311 |
11 | 43230181045 |
12 | 196a59b4187 |
13 | a65bcb6b34 |
14 | 555d3694c7 |
15 | 2d6725c1e1 |
hex | 19eaa712f7 |
111311000311 has 4 divisors (see below), whose sum is σ = 127212571792. Its totient is φ = 95409428832.
The previous prime is 111311000239. The next prime is 111311000377. The reversal of 111311000311 is 113000113111.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 111311000311 - 217 = 111310869239 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 111311000291 and 111311000300.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (111311000111) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7950785730 + ... + 7950785743.
It is an arithmetic number, because the mean of its divisors is an integer number (31803142948).
Almost surely, 2111311000311 is an apocalyptic number.
111311000311 is a deficient number, since it is larger than the sum of its proper divisors (15901571481).
111311000311 is an equidigital number, since it uses as much as digits as its factorization.
111311000311 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 15901571480.
The product of its (nonzero) digits is 9, while the sum is 13.
Adding to 111311000311 its reverse (113000113111), we get a palindrome (224311113422).
The spelling of 111311000311 in words is "one hundred eleven billion, three hundred eleven million, three hundred eleven", and thus it is an aban number.
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